题目
查询分数相同、学号不同的两条成绩,用学号与课程号打破对称重复。
知识点:自连接、去对称
运行环境:本站提供在线 SQL 运行环境。
思路
成绩表自己连自己,条件是分数相等、学号不同,得到一对记录。
用学号(必要时加课程号)规定谁在前谁在后,避免甲乙、乙甲各出现一次。
解法
-- 第35题:查询分数相同但学生不同的成绩对
-- 样例数据:学生选课 + 员工部门。最后一条 SELECT 为本题查询。
DROP TABLE IF EXISTS score;
DROP TABLE IF EXISTS course;
DROP TABLE IF EXISTS student;
DROP TABLE IF EXISTS teacher;
DROP TABLE IF EXISTS emp;
DROP TABLE IF EXISTS dept;
CREATE TABLE teacher (
tid TEXT PRIMARY KEY,
tname TEXT NOT NULL
);
CREATE TABLE student (
sid TEXT PRIMARY KEY,
sname TEXT NOT NULL,
ssex TEXT,
birthday TEXT,
city TEXT,
email TEXT
);
CREATE TABLE course (
cid TEXT PRIMARY KEY,
cname TEXT NOT NULL,
tid TEXT,
credit INTEGER
);
CREATE TABLE score (
sid TEXT,
cid TEXT,
score REAL,
exam_on TEXT
);
CREATE TABLE dept (
did TEXT PRIMARY KEY,
dname TEXT NOT NULL
);
CREATE TABLE emp (
eid TEXT PRIMARY KEY,
ename TEXT NOT NULL,
did TEXT,
manager_id TEXT,
salary INTEGER,
hired_on TEXT
);
INSERT INTO teacher(tid, tname) VALUES
('T01', '何启明'),
('T02', '陆知秋'),
('T03', '裴南'),
('T04', '江衡');
INSERT INTO student(sid, sname, ssex, birthday, city, email) VALUES
('S01', '林晓', '女', '2003-03-12', '杭州', 'linxiao@campus.test'),
('S02', '周衡', '男', '2002-11-08', '宁波', 'zhouheng@campus.test'),
('S03', '沈予', '女', '2003-06-21', '杭州', 'shenyu@campus.test'),
('S04', '韩牧', '男', '2002-07-09', '温州', 'hanmu@campus.test'),
('S05', '叶安', '女', '2004-01-30', '杭州', 'yean@campus.test'),
('S06', '方迟', '男', '2001-12-19', '嘉兴', 'fangchi@campus.test'),
('S07', '苏晚', '女', '2003-09-04', '宁波', 'suwan@campus.test'),
('S08', '程远', '男', '2004-05-17', '杭州', 'chengyuan@campus.test'),
('S09', '顾星', '女', '2002-10-28', '绍兴', 'guxing@campus.test'),
('S10', '梁野', '男', '2001-02-08', '温州', 'liangye@campus.test'),
('S11', '夏禾', '女', '2003-08-16', '杭州', 'xiahe@campus.test'),
('S12', '许川', '男', '2002-04-25', '宁波', 'xuchuan@campus.test'),
('S13', '丁南', '女', '2004-04-18', '杭州', 'dingnan@campus.test'),
('S14', '蔡河', '男', '2001-06-03', '嘉兴', 'caihe@campus.test'),
('S15', '闻青', '女', '2002-08-22', '绍兴', 'wenqing@campus.test'),
('S16', '邱石', '男', '2003-12-01', '宁波', 'qiushi@campus.test');
INSERT INTO course(cid, cname, tid, credit) VALUES
('C01', '数据库原理', 'T02', 4),
('C02', '离散数学', 'T01', 3),
('C03', '操作系统', 'T03', 4),
('C04', '计算机网络', 'T02', 3),
('C05', '编译原理', 'T01', 4),
('C06', '线性代数', 'T03', 3),
('C07', '软件工程', 'T04', 2),
('C08', '人工智能', 'T04', 3),
('C09', '毕业实习', 'T03', 1);
INSERT INTO score(sid, cid, score, exam_on) VALUES
('S01', 'C01', 88, '2025-01-08'),
('S01', 'C02', 76, '2025-01-10'),
('S01', 'C03', 91, '2025-01-12'),
('S01', 'C04', 85, '2025-01-09'),
('S01', 'C05', 72, '2025-01-11'),
('S01', 'C06', 90, '2025-01-13'),
('S01', 'C07', 68, '2025-01-08'),
('S01', 'C08', 80, '2025-02-15'),
('S02', 'C01', 70, '2025-01-08'),
('S02', 'C02', 82, '2025-01-10'),
('S02', 'C03', 64, '2025-01-12'),
('S02', 'C04', 55, '2025-01-09'),
('S03', 'C01', 90, '2025-01-08'),
('S03', 'C02', 90, '2025-01-10'),
('S03', 'C03', 85, '2025-01-12'),
('S03', 'C05', 78, '2025-01-11'),
('S04', 'C01', 45, '2025-01-08'),
('S04', 'C02', 52, '2025-01-10'),
('S04', 'C03', 40, '2025-01-12'),
('S04', 'C04', 0, '2025-01-09'),
('S05', 'C01', 79, '2025-01-08'),
('S05', 'C02', 88, '2025-01-10'),
('S05', 'C03', 70, '2025-01-09'),
('S06', 'C01', 0, '2025-01-08'),
('S06', 'C03', 58, '2025-01-12'),
('S06', 'C06', 41, '2025-01-13'),
('S07', 'C02', 94, '2025-01-10'),
('S07', 'C03', 90, '2025-01-12'),
('S07', 'C07', 88, '2025-01-11'),
('S08', 'C01', 86, '2025-01-08'),
('S08', 'C02', 61, '2025-01-10'),
('S08', 'C03', 73, '2025-01-12'),
('S08', 'C08', 69, '2025-02-15'),
('S09', 'C01', 92, '2025-01-08'),
('S09', 'C03', 81, '2025-01-12'),
('S09', 'C04', 77, '2025-01-09'),
('S10', 'C02', 55, '2025-01-10'),
('S10', 'C03', 47, '2025-01-12'),
('S11', 'C01', 77, '2025-01-08'),
('S11', 'C02', 80, '2025-01-10'),
('S11', 'C03', 79, '2025-01-12'),
('S11', 'C05', 66, '2025-01-11'),
('S12', 'C01', 60, '2025-01-08'),
('S13', 'C02', 84, '2025-01-10'),
('S13', 'C07', 91, '2025-01-11'),
('S14', 'C01', 58, '2025-01-08'),
('S14', 'C06', 73, '2025-01-13'),
('S15', 'C03', 62, '2025-01-12'),
('S15', 'C08', 0, '2025-02-15');
INSERT INTO dept(did, dname) VALUES
('D01', '研发部'),
('D02', '教学部'),
('D03', '市场部');
INSERT INTO emp(eid, ename, did, manager_id, salary, hired_on) VALUES
('E01', '陈省', 'D01', NULL, 18000, '2020-03-01'),
('E02', '吴舟', 'D01', 'E01', 12000, '2022-05-12'),
('E03', '唐宁', 'D01', 'E01', 19000, '2021-08-20'),
('E04', '沈泊', 'D02', 'E01', 15000, '2021-11-04'),
('E05', '齐末', 'D02', 'E04', 9000, '2024-04-01'),
('E06', '米白', 'D03', 'E01', 11000, '2023-02-18'),
('E07', '蓝秋', 'D03', 'E06', 8000, '2024-09-01'),
('E08', '贺川', 'D03', 'E06', 21000, '2022-12-10');
-- 本题查询
SELECT a.sid AS sid_a, a.cid AS cid_a, b.sid AS sid_b, b.cid AS cid_b, a.score
FROM score a
JOIN score b ON a.score = b.score AND (a.sid < b.sid OR (a.sid = b.sid AND a.cid < b.cid))
WHERE a.sid <> b.sid
ORDER BY a.score, a.sid, b.sid, a.cid;
运行示例
sid_a | cid_a | sid_b | cid_b | score
------+-------+-------+-------+------
S04 | C04 | S06 | C01 | 0.0
S04 | C04 | S15 | C08 | 0.0
S06 | C01 | S15 | C08 | 0.0
S02 | C04 | S10 | C02 | 55.0
S06 | C03 | S14 | C01 | 58.0
S02 | C01 | S05 | C03 | 70.0
S08 | C03 | S14 | C06 | 73.0
S09 | C04 | S11 | C01 | 77.0
S05 | C01 | S11 | C03 | 79.0
S01 | C08 | S11 | C02 | 80.0
S01 | C04 | S03 | C03 | 85.0
S01 | C01 | S05 | C02 | 88.0
S01 | C01 | S07 | C07 | 88.0
S05 | C02 | S07 | C07 | 88.0
S01 | C06 | S03 | C01 | 90.0
S01 | C06 | S03 | C02 | 90.0
S01 | C06 | S07 | C03 | 90.0
S03 | C01 | S07 | C03 | 90.0
S03 | C02 | S07 | C03 | 90.0
S01 | C03 | S13 | C07 | 91.0